Physics, SSC-Punjab Class 10. This chapter is split into 43 topics and has
1,014 practice questions. The topics covered are listed below, followed by
10 free sample questions from the chapter.
Topics in this chapter
Coefficients of linear expansion of materials22 questions
Evaporation: meaning and particle explanation21 questions
Effects of the large specific heat capacity of water20 questions
Consequences of expansion: railways, bridges, jars and pipes23 questions
Melting points, boiling points and latent heats of common substances25 questions
Exercise-style questions on expansion and specific heat21 questions
Specific heat capacity: definition, formula and units24 questions
Numericals: latent heat of fusion Q = mL25 questions
Change of state and the particle model24 questions
Thermal expansion and contraction24 questions
Superconductivity: meaning and materials23 questions
Numericals: finding the temperature change25 questions
Specific heat capacity of solids and liquids22 questions
Refrigeration without CFCs23 questions
Numericals: finding mass and specific heat capacity25 questions
Linear expansion law and formula23 questions
Latent heat: meaning and particle explanation24 questions
Uses of superconductors24 questions
Numericals: temperature change and final temperature25 questions
Factors affecting evaporation23 questions
Numericals: original length and combined expansion problems25 questions
Numericals: finding the coefficient of linear expansion25 questions
Numericals: increase in length of a heated solid25 questions
Thermal expansion of liquids: real and apparent expansion24 questions
Numericals: coefficient of volume expansion and temperature rise25 questions
Cooling caused by evaporation and sweating22 questions
Numericals: heat for several stages of heating and change of state25 questions
Numericals: increase in volume on heating25 questions
Gas pressure and the motion of particles23 questions
Thermal expansion of gases and Charles' law23 questions
Numericals: heating with an electric heater25 questions
Reasoning with ratios in thermal physics problems22 questions
Numericals: real and apparent expansion of liquids25 questions
Numericals: final length after heating25 questions
Numericals: final volume of a heated substance25 questions
Expansion: reasoning, brain teasers and misconceptions23 questions
Car engine cooling system using water21 questions
Volume expansion of solids23 questions
Consequences of expansion: thermometers, wires and everyday life22 questions
Numericals: latent heat of vaporization Q = mL25 questions
Latent heat of fusion and latent heat of vaporization22 questions
Temperature-time graph on heating ice and experiments23 questions
Sample questions: Thermal Physics
10 sample questions with the correct answer and an explanation. Try to answer each one before reading the explanation.
Q1. Which of these expands by the same amount as a steel rod of equal length for the same temperature rise?
A. Concrete, as both have &alpha(correct answer)
B. A gold rod, since both of them are dense
C. A tungsten rod, since both are very hard
D. A silver rod, since both of them are shiny
Answer: A.Equal α gives equal expansion for equal original length and ΔT; steel and concrete share 1.2 × 10⁻⁵ K⁻¹. Matching concrete and steel is also why reinforced concrete does not crack.
Q2. The coefficient of linear expansion of aluminium is 2.4 × 10⁻⁵ K⁻¹. Find the increase in length of a 1.5 m aluminium bar when its temperature rises from 25 °C to 125 °C.
A. 3.6 mm(correct answer)
B. 36 mm
C. 1.504 m
D. 0.36 mm
Answer: A.ΔL = α L₀ ΔT = 2.4 × 10⁻⁵ × 1.5 × 100 = 3.6 mm. (Using the final temperature instead of ΔT, or slipping a power of ten, gives the wrong values.)
Q3. What is ΔL for a brass wire of original length 0.8 m heated through 200 K, if α = 1.9 × 10⁻⁵ K⁻¹?
A. 3.27 mm
B. 3.04 mm(correct answer)
C. 30.4 mm
D. 0.803 m
Answer: B.ΔL = α L₀ ΔT = 1.9 × 10⁻⁵ × 0.8 × 200 = 3.04 mm. (Using the final temperature instead of ΔT, or slipping a power of ten, gives the wrong values.)
Q4. What is ΔL for a copper wire of original length 2.5 m heated through 200 K, if α = 1.7 × 10⁻⁵ K⁻¹?
A. 9.35 mm
B. 85 mm
C. 2.509 m
D. 8.5 mm(correct answer)
Answer: D.ΔL = α L₀ ΔT = 1.7 × 10⁻⁵ × 2.5 × 200 = 8.5 mm. (Using the final temperature instead of ΔT, or slipping a power of ten, gives the wrong values.)
Q5. A silver rod is 1.2 m long at 20 °C. By how much does it lengthen when heated to 80 °C? (α = 1.93 × 10⁻⁵ K⁻¹)
A. 13.9 mm
B. 1.39 mm(correct answer)
C. 0.139 mm
D. 1.85 mm
Answer: B.ΔL = α L₀ ΔT = 1.93 × 10⁻⁵ × 1.2 × 60 = 1.39 mm. (Using the final temperature instead of ΔT, or slipping a power of ten, gives the wrong values.)
Q6. The coefficient of linear expansion of gold is 1.3 × 10⁻⁵ K⁻¹. Find the increase in length of a 0.5 m gold bar when its temperature rises from 25 °C to 325 °C.
A. 1.95 mm(correct answer)
B. 19.5 mm
C. 0.195 mm
D. 0.502 m
Answer: A.ΔL = α L₀ ΔT = 1.3 × 10⁻⁵ × 0.5 × 300 = 1.95 mm. (Using the final temperature instead of ΔT, or slipping a power of ten, gives the wrong values.)
Q7. What is ΔL for a Pyrex glass wire of original length 0.25 m heated through 300 K, if α = 0.4 × 10⁻⁵ K⁻¹?
A. 0.32 mm
B. 250 mm
C. 0.3 mm(correct answer)
D. 3 mm
Answer: C.ΔL = α L₀ ΔT = 0.4 × 10⁻⁵ × 0.25 × 300 = 0.3 mm. (Using the final temperature instead of ΔT, or slipping a power of ten, gives the wrong values.)
Q8. What is ΔL for a copper wire of original length 0.6 m heated through 100 K, if α = 1.7 × 10⁻⁵ K⁻¹?
A. 1.02 mm(correct answer)
B. 0.601 m
C. 10.2 mm
D. 0.102 mm
Answer: A.ΔL = α L₀ ΔT = 1.7 × 10⁻⁵ × 0.6 × 100 = 1.02 mm. (Using the final temperature instead of ΔT, or slipping a power of ten, gives the wrong values.)
Q9. A ordinary glass rod is 1.5 m long at 20 °C. By how much does it lengthen when heated to 120 °C? (α = 0.9 × 10⁻⁵ K⁻¹)
A. 1.62 mm
B. 0.135 mm
C. 13.5 mm
D. 1.35 mm(correct answer)
Answer: D.ΔL = α L₀ ΔT = 0.9 × 10⁻⁵ × 1.5 × 100 = 1.35 mm. (Using the final temperature instead of ΔT, or slipping a power of ten, gives the wrong values.)
Q10. A liquid and its glass flask have the same coefficient of volume expansion. What apparent expansion is observed when they are heated together?
A. Twice the real expansion
B. Cannot be said at all
C. Zero(correct answer)
D. Equal to the real expansion
Answer: C.Real = apparent + container; if container expansion equals the liquid's real expansion, the apparent expansion is zero (the level does not change).